(4x-3)^2-x(7x-6)=2

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Solution for (4x-3)^2-x(7x-6)=2 equation: 



(4x-3)^2-x(7x-6)=2

We move all terms to the left:

(4x-3)^2-x(7x-6)-(2)=0

We multiply parentheses

-7x^2+(4x-3)^2+6x-2=0

We add all the numbers together, and all the variables

-7x^2+6x+(4x-3)^2-2=0

We move all terms containing x to the left, all other terms to the right

-7x^2+6x+(4x-3)^2=2

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